WebHow many terms of the AP:24,21,18.... must be taken so that their sum is 78 ? Hard Solution Verified by Toppr Given: 24,21,18,... are in A.P a=24,d=21−24=−3 Sum = 2n[2a+(n−1)d] ⇒78= 2n[2×24+(n−1)(−3)] ⇒156=n[48−3n+3] ⇒156=n[51−3n] ⇒3n 2−51n+156=0 ⇒3n 2−12n−39n+156=0 ⇒3n(n−4)−39(n−4)=0 ⇒(n−4)(3n−39)=0 ∴n=4,n= … Web28 mrt. 2024 · We know that the sum of all terms of an A.P. is given by, S n = n 2 [ 2 a + ( n − 1) d], ……… (i) this can also be written as: S n = n 2 [ a + l], ………. (ii) here l = last term = a + (n-1)d. Here given that, a = 27 and S n = 0 We know that d = common difference = a 2 − a 1 = 24 − 27 = − 3. Putting these values in equation (i), we get
How many terms of the A.P. : 24, 21, 18, - Sarthaks
Web14 jan. 2024 · Best answer Solution: Given AP is -6, -11/2, -5… Here a = –6, d = (–11/2) + 6 = 1/2 Sum of n terms of AP, Sn = – 25 Using sum of n term of AP formula ⇒ n2 – 25n + 100 = 0 ⇒ n2 – 20n – 5n + 100 = 0 ⇒ n (n – 20) – 5 (n – 20) = 0 ⇒ (n – 20) (n – 5) = 0 ⇒ (n – 20) = 0 or (n – 5) = 0 ∴ n = 20 or n = 5 ← Prev Question Next Question → Web4 mrt. 2024 · How many Terms of the AP 24 21 18 must be taken so that their Sum is 78 Class 10 Maths Chapter 5 Example 13Example 13 : How many terms of the AP : 24, 21, ... rawhide season 3 episode 27
How many terms of the A.P. 27, 24, 21, ...... should be …
WebFind The Sum Of 21 And 15, , , , , , , 0, Example 13 - How many terms of AP: 24, 21, 18 must - Finding numbe, www.teachoo.com, 945 x 945, jpeg, , 20, find-the-sum-of ... Web25 aug. 2024 · Click here 👆 to get an answer to your question ️ Which term of the AP: 27, 24, 21, is zero? ytbrijesh ytbrijesh 25.08.2024 Math Secondary School answered Which term of the AP: 27, 24, 21, is zero? See ... How Many soaps measuring 8 cm X 4 cm X 2cm can be arranged in this box ? class interval 1-3 3-5 5-7 7-9 frequency 12 22 27 ... Web25 jul. 2024 · let first term of the AP be a1= -10 second term of the AP be a2=-7 and common difference be d. d=a2-a1 d=-7- (-10) d=-7+10 d=3 so common difference is d=3 we know that, Sum of n terms in the AP is, Sn=n/2 [2a1+ (n-1)d] 104=n/2 [2×-10 + (n-1)3] 104×2=n [-20+3n-3] 208=n [3n-23] 208=3n^2-23n 3n^3-23n-208=0 3n^2-39n+16n-208=0 … rawhide season 3 episode 24